Indian Institute of Technology Roorkee (IIT Roorkee)

Location: Roorkee, Uttarakhand10000+ studentsEstablished: Est. 184710-point scale

IIT Roorkee CGPA to Percentage Calculator

Formula:CGPA × 10

Enter your CGPA value between 0 and 10

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Note: This calculator applies the commonly used IIT Roorkee formula (CGPA × 10). Conversion rules can change between regulations and programmes — always confirm your final percentage against your official IIT Roorkeegrade card or your department before using it for applications.

IIT Roorkee CGPA to Percentage Formula

Official Conversion Formula:

Percentage = CGPA × 10

Indian Institute of Technology Roorkee uses a 10-point grading system. To convert your CGPA to percentage, multiply your CGPA by 10. For example, if your CGPA is 8.5, your percentage would be 85.00%.

The same formula applies to a single semester: multiply your SGPA by the same factor to get that semester's percentage. Use your overall CGPA for your final percentage.

Maintained by the CGPAPercent.in editorial team. Need the reverse? Convert percentage to CGPA.

IIT Roorkee CGPA to Percentage Table

CGPAPercentage (CGPA × 10)
10.0100.00%
9.595.00%
9.090.00%
8.585.00%
8.080.00%
7.575.00%
7.070.00%
6.565.00%
6.060.00%

Quick reference for common IIT Roorkee CGPA values. For any exact value, use the calculator above.

IIT Roorkee Division Classification

DivisionMin. PercentageMin. CGPA
First Class60%6
Second Class50%5
Pass40%4

IIT Roorkee Grading System

GradeMarks RangeGrade Point
A90 - 10010
AB80 - 899
BB70 - 798
BC60 - 697
CC50 - 596

* Grade system based on official university documents. Please verify with your department.

About Indian Institute of Technology Roorkee

Indian Institute of Technology Roorkee (IIT Roorkee) is one of the oldest and most prestigious technical institutions in Asia, originally established in 1847 as the College of Civil Engineering. It became an IIT in 2001. The institute offers undergraduate, postgraduate, and doctoral programs in engineering, sciences, management, and architecture.

10
Point Scale
×10
Multiplier
1847
Established
10000+
Students

How Indian Institute of Technology Roorkee Converts CGPA to Percentage

While some institutions require complicated multipliers, the Indian Institute of Technology Roorkee (IIT Roorkee) perfectly matches a plain CGPA × 10 scale. Established in Roorkee, Uttarakhand in 1847, this historic institute keeps its 10-point grading system completely transparent. The official conversion formula is simply Percentage = CGPA × 10.

Because the multiplier is a flat ten, calculating your percentage for job applications or higher studies is seamless. For example, a CGPA of 8.0 converts directly to 80%. Knowing exactly where your grades stand is crucial for degree classifications. To graduate with a First Class degree, you must hit a minimum of 60.0%. Your actionable target is maintaining at least a CGPA of 6.0. If your score slips to a CGPA of 5.0, you will fall into the Second Class bracket at 50.0%. The absolute minimum requirement to earn a Pass is a CGPA of 4.0 (40.0%).

Frequently Asked Questions

What is the most common conversion mistake students make at IIT Roorkee?
The biggest mistake is applying a generic 9.5 multiplier out of habit. Since IIT Roorkee uses exactly CGPA × 10, using a lower multiplier artificially reduces your percentage on resumes. Under the official formula, a CGPA of 9.5 correctly equals 95%.

How much is a 7.5 CGPA at IIT Roorkee?
A CGPA of 7.5 is exactly 75%.

What does a 6.5 CGPA convert to?
A CGPA of 6.5 converts to 65%, keeping your academic profile safely inside the First Class category.

For other universities, use our main CGPA to Percentage Calculator — accurate, official formulas for 57+ universities.

Frequently Asked Questions - IIT Roorkee